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0=3+23.5x-4.9x^2
We move all terms to the left:
0-(3+23.5x-4.9x^2)=0
We add all the numbers together, and all the variables
-(3+23.5x-4.9x^2)=0
We get rid of parentheses
4.9x^2-23.5x-3=0
a = 4.9; b = -23.5; c = -3;
Δ = b2-4ac
Δ = -23.52-4·4.9·(-3)
Δ = 611.05
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23.5)-\sqrt{611.05}}{2*4.9}=\frac{23.5-\sqrt{611.05}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23.5)+\sqrt{611.05}}{2*4.9}=\frac{23.5+\sqrt{611.05}}{9.8} $
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